Math Problem! Any Takers?
- Thread starter Emperor
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1 in 300
each ticket has 12 chances out of 3600 or 1 in 300.
there are a total of 3600 (12x300) numbers available, each ticket has 12 numbers so the odds are 1 in 300 if they only call out one number, but if they call out 12 numbers then it would still be 1 in 300.
been a while since i took statistics, but this would be my answer.
each ticket has 12 chances out of 3600 or 1 in 300.
there are a total of 3600 (12x300) numbers available, each ticket has 12 numbers so the odds are 1 in 300 if they only call out one number, but if they call out 12 numbers then it would still be 1 in 300.
been a while since i took statistics, but this would be my answer.
What is the parameter for the win? A random number between 1-100? The powerball number on Saturdays? If none of those and you say that there is only one ticket that holds a win. then you have a 1 in 300 chance of success. Not enough data provided.
Winners are re-entered until all 12 items have been won. Conceivably; 1 ticket could win all 12 items.
It's a raffle, a drawn ticket wins...parameter is dumb luck.
That's easy, 12 in 300, right?
300 stubs to choose from, random single draw; 1st winner goes back in the barrel with the other 299. The 2nd of the 12 items is then drawn; and the process continues until all items are gone.
Also to this^, the odds are going to change as each item is removed from the mix. So there must be a sliding scale of odds that will decrease as any of the 12 items are removed from the initial 300.
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No, now that I look at it; how can the odds of winning be the same if you have 12 items to start with and you haven't won any of the items by the time the final item is drawn. Your chances of winning one of the items when there were 12 available is surely better than when they only have 1 left.
Because when there are none left, your chances of winning are zero.
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