Lol. You guys are over complicating this.
1 winner out of 300 tickets With Replacement 12 times.
12games * 1/300 odds = 12/300
=6/150
=3/75
=1/25 to win at the beginning of the drawings.
Therefore we can derived our own equation!
Let n= # of games already played
(12-n) / 300 = p(x)
Right, my dissertation were on the odds of winning one prize. And this formula works for of you buy a ticket after drawings started.
11.79/300 are the odds of winning ONE prize. 12/300 or 1/25 are the odds of winning PERIOD (that is any number of prizes). 12-11.79=0.21 are the odds of winning MULTIPLE prizes and 300-12=288 are the odds of winning NO prizes.
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